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Column Buckling Calculation

Column Buckling Calculator

Estimate Euler critical load, effective length, and slenderness for compression members with common end conditions.

Enter length in meters, E in GPa, inertia in cm^4, area in cm^2, and applied axial load in kN.

Buckling Inputs

End condition

Member data

Use the end condition that best matches the expected rotational restraint.

Use the weaker-axis inertia when buckling can occur about multiple axes.

Area is used to calculate the radius of gyration and slenderness.

Applied load is compared directly with the ideal Euler critical load.

Buckling Diagram
Effective length3.20 mOriginal axisBuckled shape
Euler critical load12,650.25 kN
Load ratio P / Pcr0.014
Slenderness ratio23.08
Effective length3.20 m
Stability Summary
End conditionPinned-Pinned
Effective length factor K1.000
Radius of gyration r13.87 cm
Euler stress Fe3,892.38 MPa
Load margin Pcr - P12,470.25 kN
Buckling Formula

Effective length

General form

L_e = K L

With current values

L_e = 1.000 * 3.20

Calculated result

L_e = 3.20 m

Euler critical load

General form

P_cr = pi^2 E I / L_e^2

With current values

P_cr = pi^2 * 210 * 6,250 / 3.20^2

Calculated result

P_cr = 12,650.25 kN

Slenderness ratio

General form

lambda = L_e / r, r = sqrt(I / A)

With current values

lambda = 3.20 / sqrt(6,250 / 33)

Calculated result

lambda = 23.08

This screen applies classical Euler elastic buckling and is most reliable for slender columns before inelastic or code-specific checks.

Model Assumptions
  • The column is straight, prismatic, and loaded concentrically.
  • Material behavior is linear elastic up to the predicted buckling load.
  • Only ideal Euler global buckling is screened here; local buckling and imperfections are excluded.
Engineering Reading
This column is relatively stocky; elastic Euler buckling is only a screening check.
Calculation Basis
MethodEuler buckling theory with effective-length-factor method
ScopeColumn Buckling Calculator for elastic preliminary compression-member review
ReviewTechnically reviewed: 2026-04-15

Assumptions & Limits

  • The model screens ideal global Euler buckling only and does not include local buckling or material nonlinearity.
  • Imperfections, eccentricity, and frame sway effects need separate engineering review.
  • K-factors are modeling assumptions about end restraint and should be treated as a sensitivity study when restraint is uncertain.

Reference Basis

When this column buckling calculation is useful
  • Early screening of steel, timber, or generic compression members when global elastic buckling is the first question.
  • Quick comparison of how support restraint changes effective length and Euler critical load.
  • Teaching, QA, and hand-check support before you move into code reduction factors or member design clauses.
End condition guide
Pinned-PinnedUse when both ends rotate freely. Baseline Euler case with K = 1.0.
Fixed-FixedUse when both ends are rotationally restrained. Stronger buckling resistance with K = 0.5.
Fixed-PinnedUse when one end is restrained and the other can rotate. Intermediate case with K = 0.7.
Cantilever ColumnUse when the top is free and the base is fixed. Most flexible case here with K = 2.0.
What to review after the Euler check
  • Compare the buckling axis you modeled with the real weak-axis behavior of the section.
  • Review imperfections, eccentricity, sway, and frame action before treating the Euler load as a design value.
  • Move into slenderness, effective-length, and section-property pages when you need a tighter preliminary read.
Column Buckling FAQ
  • Is this column buckling calculator enough for final design? No. It is a clean Euler buckling calculation for preliminary review. Final design still needs the governing code method, imperfections, and section-specific resistance checks.
  • Why does the end condition change the result so much? Because the effective length factor changes the buckling length directly. A small change in K can shift the Euler critical load a lot.
  • What if the column can buckle about more than one axis? Check the weaker axis first. If both axes are possible, compare both weak-axis and strong-axis inertia rather than trusting one default value.